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GATE | GATE-CS-2005 | Question 82

Consider the following C-function: C
double foo (int n)
{
    int i;
    double sum;
    if (n = = 0) return 1.0;
    else
    {
        sum = 0.0;
        for (i = 0; i < n; i++)
            sum += foo (i);
        return sum;
    }
}
Suppose we modify the above function foo() and store the values of foo (i), 0 < = i < n, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:

(A)

O(1)

(B)

O(n)

(C)

O(n!)

(D)

O(nn)

Answer

Please comment below if you find anything wrong in the above post
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