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GATE | GATE-IT-2004 | Question 53
An array of integers of size n can be converted into a heap by adjusting the heaps rooted at each internal node of the complete binary tree starting at the node ⌊(n - 1) /2⌋, and doing this adjustment up to the root node (root node is at index 0) in the order ⌊(n - 1)/2⌋, ⌊(n - 3)/ 2⌋, ....., 0. The time required to construct a heap in this manner is
(A)
O(log n)
(B)
O(n)
(C)
O (n log log n)
(D)
O(n log n)
Answer
Please comment below if you find anything wrong in the above post
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